How do you simplify $\sqrt{8 - x^{2}}$ $sqrt(8-x^2)$ ?

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How do you simplify $\sqrt{8 - x^{2}}$ $sqrt(8-x^2)$ ?

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Answer 1 · 2017-06-18T01:11:13

$2 \sqrt{2} - x$ $2sqrt2-x$

Explanation:

To simplify $\sqrt{8 - x^{2}}$ $sqrt(8-x^2)$ you can approach it as:

$\sqrt{8}$ $sqrt(8$ $&$ $&$ $\sqrt{- x^{2}}$ $sqrt(-x^2)$

Since this isn't a perfect $\sqrt{8}$ $sqrt(8$ you can break it down into:

$\sqrt{4} \times \sqrt{2}$ $sqrt(4)xxsqrt(2)$

Since $\sqrt{4}$ $sqrt(4)$ is a perfect square we now get $2$ $2$
But we cannot break down $\sqrt{2}$ $sqrt(2)$ any further so we leave it how it is.
This is what we got now:

$2 \sqrt{2}$ $2sqrt2$

As for $\sqrt{- x^{2}}$ $sqrt(-x^2)$ it can be rewritten as:

$(-x^cancel2)^(cancel(1/2))=-x$

$(-x^2)^(1/2)=-x^(2/2)=-x$

So our final answer is $2sqrt2-x$

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How do you simplify $\sqrt{8 - x^{2}}$ $sqrt(8-x^2)$ ?

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How do you simplify sqrt(8-x^2)√8−x2sqrt(8-x^2)?

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How do you simplify $\sqrt{8 - x^{2}}$ $sqrt(8-x^2)$ ?