The area of a rectangular playing field is 192square meters. The length of the field is x+12 and the width is x-4. How do you calculate x by using quadratic formula?
1 Answer
Explanation:
We know that the area formula for a rectangle is:
#"length" color(white)"." xx color(white)"." "width" color(white)"." = color(white)"." "area"#
So, we can plug these numbers in and then write everything in terms of a quadratic which we can solve with the quadratic formula.
#(x+12) xx (x-4) = 192#
Let's use the FOIL method to expand the left side.
#underbrace((x)(x)) _ "First" + underbrace((x)(-4)) _ "Outer" + underbrace((12)(x)) _ "Inner" + underbrace((12)(-4))_"Last" = 192#
#x^2 + (-4x) + (12x) + (-48) = 192#
#x^2 + 8x - 48 = 192#
Now subtract
#x^2 + 8x - 240 = 0#
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This is a quadratic, so we can use the quadratic formula to solve it.
#a = 1#
#b = 8#
#c = -240#
#x = (-b+-sqrt(b^2-4ac))/(2a)#
Now plug in all of those values and simplify.
#x = (-(8)+-sqrt((8)^2-4(1)(-240)))/(2(1))#
#x = (-8+-sqrt(64+960))/2#
#x = (-8+-sqrt1024)/2#
Note that
#x = (-8+-sqrt(32^2))/2#
#x = (-8+-32)/2#
#x = -4+-16#
This means our two values of
#x = -4-16 " " and " " x = -4+16#
#x = -20 " " and " " x = 12#
Remember that
#x = 12#
Final Answer