How do you simplify #sqrt3/sqrt7#?
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"Which following pairs of atoms, have a lower electron affinity? a) Ca,K b) I,F c) Li, Ra. I seriously don't know anything about electron affinity all ik that it can buy another element"
1 Answer
Aug 13, 2017
Explanation:
To simplify
#sqrt3/sqrt7 * color(blue)(sqrt7/sqrt7) = sqrt21/7#
