How do you simplify $(9x)^(a/b)$ ?

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Answer 1 · 2017-09-23T05:33:56

Rearrange fraction exponent into a radical.

When the exponent is a fraction, the denominator is paired with the terms as it's own exponent.

This pairing is under a radical, with the numerator as the index.

As a result, you get something like this:

$(9x)^(a/b)=root(b)((9x)^a)$

P.S. There may be other ways to simplify the value you gave us. The radical route was the first one I thought of.

Hope this helps :)

How do you simplify (9x)^(a/b)(9x)^(a/b)?