How do you simplify the expression #sqrt(2/3)+sqrt6#?

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Answer 1 · 2017-10-11T04:10:43

#4sqrt(2/3)#

I can rewrite the second term in the expression like so:

#sqrt(2/3)+sqrt(18/3)#

Then factor out a #2/3#:

#sqrt(2/3)+sqrt(9*2/3)#

Use properties of square roots:

#sqrt(2/3)+sqrt(9)*sqrt(2/3)#

Take the square root of #9#:

#1sqrt(2/3)+3sqrt(2/3)#

Add like radicals:

#4sqrt(2/3)#