How do you differentiate f(x)=xe^xcscx? Calculus Differentiating Trigonometric Functions Derivatives of y=sec(x), y=cot(x), y= csc(x) 1 Answer Manikandan S. Nov 2, 2017 Use chain rule Explanation: f(x) = xe^xcscx f'(x) = e^xcscx+xe^xcscx-xe^xcscxcotx = e^xcscx(1+x-xcotx) Answer link Related questions What is Derivatives of y=sec(x) ? What is the Derivative of y=sec(x^2)? What is the Derivative of y=x sec(kx)? What is the Derivative of y=sec ^ 2(x)? What is the derivative of y=4 sec ^2(x)? What is the derivative of y=ln(sec(x)+tan(x))? What is the derivative of y=sec^2(x)? What is the derivative of y=sec^2(x) + tan^2(x)? What is the derivative of y=sec^3(x)? What is the derivative of y=sec(x) tan(x)? See all questions in Derivatives of y=sec(x), y=cot(x), y= csc(x) Impact of this question 6638 views around the world You can reuse this answer Creative Commons License