How do you write the point slope form of the equation given (4,-5) and m=6?

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Answer 1 · 2017-11-15T09:45:50

$y = 6 x - 29$ $y=6x-29$
graph{y=6x-29 [-10, 10, -5, 5]}

The formula to find the equation is $y = m x + b$ $y=mx+b$

Since we know that $m = 6$ $m=6$ , the equation we have so far would be $y = 6 x + b$ $y=6x+b$ .

Now, we will find $b$ $b$ .

Plug in $(4, - 5)$ $(4, -5)$ where $x = 4$ $x=4$ and $y = - 5$ $y=-5$

$- 5 = 6 \cdot 4 + b$ $-5=6*4+b$

Switch sides:
$6 \cdot 4 + b = - 5$ $6*4+b=-5$

Multiply the numbers:
$24 + b = - 5$ $24+b=-5$

Subtract $24$ $24$ from both sides:
$24 + b - 24 = - 5 - 24$ $24+bcolor(red)-color(red)24=-5color(red)-color(red)24$

Simplify:
$b = - 29$ $b=-29$

Therefore, the whole equation is:
$y = 6 x - 29$ $y=6x-29$ .

Answer 2 · 2017-11-15T10:04:19

$y + 5 = 6 (x - 4)$ $y+5=6(x-4)$

Remember that the point-slope form equation looks like this:

$y - k = m (x - h)$ $y-k=m(x-h)$

Where $h$ $h$ and $k$ $k$ represents a point on the line and $m$ $m$ is the slope.

The point should have the coordinates like this: $(h, k)$ $(h,k)$

What we have to do is substitute the values in like so:

$y - k = m (x - h)$ $y-k=m(x-h)$
$y - (- 5) = 6 (x - 4)$ $y-(-5)=6(x-4)$
So the answer must be:
$y + 5 = 6 (x - 4)$ $y+5=6(x-4)$

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