How do you write the point slope form of the equation given (4,-5) and m=6?

2 Answers
Nov 15, 2017

y=6x-29y=6x29
graph{y=6x-29 [-10, 10, -5, 5]}

Explanation:

The formula to find the equation is y=mx+by=mx+b

Since we know that m=6m=6, the equation we have so far would be y=6x+by=6x+b.

Now, we will find bb.

Plug in (4, -5)(4,5) where x=4x=4 and y=-5y=5

-5=6*4+b5=64+b

Switch sides:
6*4+b=-564+b=5

Multiply the numbers:
24+b=-524+b=5

Subtract 2424 from both sides:
24+bcolor(red)-color(red)24=-5color(red)-color(red)2424+b24=524

Simplify:
b=-29b=29

Therefore, the whole equation is:
y=6x-29y=6x29.

Nov 15, 2017

y+5=6(x-4)y+5=6(x4)

Explanation:

Remember that the point-slope form equation looks like this:

y-k=m(x-h)yk=m(xh)

Where hh and kk represents a point on the line and mm is the slope.

The point should have the coordinates like this: (h,k)(h,k)

What we have to do is substitute the values in like so:

y-k=m(x-h)yk=m(xh)
y-(-5)=6(x-4)y(5)=6(x4)
So the answer must be:
y+5=6(x-4)y+5=6(x4)

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