How do you simplify #(4 + sqrt2) (3 + sqrt2)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Victor Nov 25, 2017 # 14+7sqrt2 # Explanation: Cross multiplication # (4+sqrt2)(3+sqrt2) = 12 + 4sqrt2 + 3sqrt2 +2 = 14 + 7sqrt2 # Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1489 views around the world You can reuse this answer Creative Commons License