How do you find the roots, real and imaginary, of y=x23x2(x1)2 using the quadratic formula?

1 Answer
Jan 26, 2018

Imaginary Roots , 1±23i6

Explanation:

Simply this equation to get : y=ax2+bx+c

y=x23x2(x22x+1)
y=x23x2x2+4x2

y=3x2+x2

comparing with: y=ax2+bx+c

we get a=3 , b=1, c=2

using the quadratic formula:

b±b24ac2a
1±124(3)(2)2(3)

Solve further and get
answer = 1±23i6