How do you solve $sqrt(2x - 3) = 5$ ?

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Answer 1 · 2018-03-02T09:52:54

We have, $sqrt(2x-3)=5$
Squaring on both sides,we have,
$2x-3=(5)^2$
or, $2x=25+3$
or, $x=28//2$ which is 14.

Thus,x= $14$

Answer 2 · 2018-03-02T09:53:07

$x=14$

$sqrt(2x−3)=5$
$2x-3=25$
$2x=25+3$
$x=28/2$
$x=14$

How do you solve sqrt(2x - 3) = 5sqrt(2x - 3) = 5?