How do you do square root of 98 divided by square root of 18?

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Answer 1 · 2018-03-03T22:31:00

#sqrt(98) / sqrt(18) = 2.333333333...#

For the equation:

#sqrt(98) / sqrt(18)#

You must

#sqrt(98) = 9.899494937...#

#sqrt(18) = 4.242640687...#

#(9.899494937...)/ (4.242640687...) = 2.333333333...#

Or rounded up to
#2.3# (repeating)

Answer 2 · 2018-03-03T22:36:51

#7/3#

#sqrt98/sqrt18#

We can start by factoring out a perfect square from #sqrt98#. Since #2*49=98#, #color(blue)(sqrt2*sqrt49)=sqrt98#.

Next, let's factor out a perfect square from #sqrt18#. Since #2*9=18#, #color(blue)(sqrt2*sqrt9)=sqrt18#.

Our new fraction is as follows:

#(sqrt2*sqrt49)/(sqrt2*sqrt9)#

This can be simplified as:
#(7cancel(sqrt2))/(3cancel(sqrt2))#

#7/3#, as if you have the same things on the numerator and denominator, they will cancel.