How do you simplify $(g + 6) (g + 4)$ $(g + 6)(g + 4)$ ?

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Answer 1 · 2018-03-11T21:31:37

$g^{2} + 10 g + 24$ $g^2 + 10g + 24$

So you're going to want to distribute the terms.

First, multiply both terms in $(g + 4)$ $(g+4)$ by $g$ $g$ from $(g + 6)$ $(g +6)$ .

$g (g + 4) = g^{2} + 4 g$ $g(g+4) = g^2 +4g$

then multiply $(g + 4)$ $(g+4)$ by $6$ $6$ from $(g + 6)$ $(g+6)$

$6 (g + 4) = 6 g + 24$ $6(g+4)= 6g+24$

Now add the two products,

$g^{2} + 4 g + 6 g + 24$ $g^2 +4g + 6g + 24$

$g^{2} + 10 g + 24$ $g^2 +10g +24$

How do you simplify (g + 6)(g + 4)(g+6)(g+4)(g + 6)(g + 4)?