How do you multiply (4x-2)(4x+2)(4x−2)(4x+2)?

1 Answer
AltairSafir
Mar 28, 2018

Multiply each factor with each factor.

Explanation:

(4x-2)(4x+2)=4x*4x+4x*2-2*4x-2*2=(4x−2)(4x+2)=4x⋅4x+4x⋅2−2⋅4x−2⋅2=
=4^2x^2+(8-8)x-4=16x^2-4=42x2+(8−8)x−4=16x2−4

You can remember this formula:
(a+b)(a-b)=a^2-b^2(a+b)(a−b)=a2−b2

(a-b)(a+b)=a*a+a*b-b*a-b*b=(a−b)(a+b)=a⋅a+a⋅b−b⋅a−b⋅b=
=a^2+(ab-ba)-b^2=a^2-b^2=a2+(ab−ba)−b2=a2−b2

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