How do you factor $49 x^{2} - 36$ $49x^2-36$ ?

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How do you factor $49 x^{2} - 36$ $49x^2-36$ ?

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Answer 1 · 2018-03-29T13:22:07

$(7 x + 6) (7 x - 6)$ $(7x+6)(7x-6)$

Explanation:

$49 x^{2} - 36 =$ $49x^2−36 =$
$7^{2} x^{2} - 6^{2} =$ $7^2x^2−6^2 =$
${(7 x)}^{2} - 6^{2} =$ $(7x)^2-6^2=$
$(7 x + 6) (7 x - 6)$ $(7x+6)(7x-6)$
because $a^{2} - b^{2} = (a + b) (a - b)$ $a^2-b^2=(a+b)(a-b)$

Answer 2 · 2018-03-29T13:24:10

$(7 x + 6) (7 x - 6)$ $(7x+6)(7x-6)$

Explanation:

Note that $49 = 7^{2}$ $49=7^2$ and $36 = 6^{2}$ $36=6^2$

So we have $7^{2} x^{2} - 6^{2} = {(7 x)}^{2} - 6^{2}$ $7^2x^2 - 6^2 = (7x)^2-6^2$ .

This is in the form $a^{2} - b^{2}$ $a^2-b^2$ which can be factored to $(a + b) (a - b)$ $(a+b)(a-b)$

So here we have $a = 7 x$ $a = 7x$ and $b = 6$ $b = 6$ , so that would be $(7 x + 6) (7 x - 6)$ $(7x+6)(7x-6)$

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How do you factor $49 x^{2} - 36$ $49x^2-36$ ?

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