How do you factor $49x^2-36$ ?

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Answer 1 · 2018-03-29T13:22:07

$(7x+6)(7x-6)$

$49x^2−36 =$
$7^2x^2−6^2 =$
$(7x)^2-6^2=$
$(7x+6)(7x-6)$
because $a^2-b^2=(a+b)(a-b)$

Answer 2 · 2018-03-29T13:24:10

$(7x+6)(7x-6)$

Note that $49=7^2$ and $36=6^2$

So we have $7^2x^2 - 6^2 = (7x)^2-6^2$ .

This is in the form $a^2-b^2$ which can be factored to $(a+b)(a-b)$

So here we have $a = 7x$ and $b = 6$ , so that would be $(7x+6)(7x-6)$

How do you factor 49x^2-3649x^2-36?