Factor Polynomials Using Special Products
Key Questions
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Answer:
You identify special products by their values if its a perfect square or cubes..
Explanation:
For examples;
Difference of two squares is:
#x^2 - y^2 = (x + y) (x - y)# #(x + y)^2 = x^2 + y^2 + 2ab# #(x - y)^2 = x^2 + y^2 - 2ab# Note:
#(x - y)^2 != x^2 - y^2# This Link might help!
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There's a single formula which refers to "difference of squares":
#a^2 - b^2 = (a-b)(a+b)# If we use FOIL we can prove that. Difference of squares method would refer to doing something like the following:
#x^2 -1 = (x - 1)(x+1) #
#x^2 - 4 = (x-2)(x+2) # Or even the double application here
#x^4 - 16 = (x^2)^2 - 4^2 = (x^2 - 4)(x^2 + 4) = (x-2)(x+2)(x^2+4) # -
Look for numbers that are perfect squares or perfect cubes.
There are many special products in factoring. Three of the most well-known are
#(x+y)^2=x^2+2xy+y^2#
and
#(x−y)^2=x-2xy+y^2#
and
#(x+y)(x−y)=x^2−y^2# Two less well-known ones are
#x^3+y^3=(x+y)(x^2−xy+y^2)#
and
#x^3−y^3=(x−y)(x^2+xy−y^2)#
Note that in an actual problem, x and y can be any number or variable. Hope this helped!
Questions
Polynomials and Factoring
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Polynomials in Standard Form
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Addition and Subtraction of Polynomials
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Multiplication of Monomials by Polynomials
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Multiplication of Polynomials by Binomials
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Special Products of Polynomials
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Monomial Factors of Polynomials
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Zero Product Principle
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Factorization of Quadratic Expressions
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Factor Polynomials Using Special Products
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Factoring by Grouping
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Factoring Completely
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Probability of Compound Events