How do you factor $1 - {(x - y)}^{2}$ $1-(x-y)^2$ ?

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How do you factor $1 - {(x - y)}^{2}$ $1-(x-y)^2$ ?

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Answer 1 · 2016-08-08T15:36:29

$= (1 - x + y) (1 + x - y)$ $=(1-x+y)(1+x-y)$

Explanation:

Since $a^{2} - b^{2}$ $a^2-b^2$
$(a - b) (a + b)$ $(a-b)(a+b)$
$1 - {(x - y)}^{2}$ $1-(x-y)^2$
$= 1^{2} - {(x - y)}^{2}$ $=1^2-(x-y)^2$
$= (1 - (x - y)) (1 + (x - y))$ $=(1-(x-y))(1+(x-y))$
$= (1 - x + y) (1 + x - y)$ $=(1-x+y)(1+x-y)$

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How do you factor $1 - {(x - y)}^{2}$ $1-(x-y)^2$ ?

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