How do you factor $16 x^{2} - 36$ $16x^2-36$ using the difference of squares?

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How do you factor $16 x^{2} - 36$ $16x^2-36$ using the difference of squares?

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Answer 1 · 2014-10-29T01:06:16

$16 x^{2} - 36$ $16x^2 - 36$ is the difference of two squares and will always factor in the following pattern: $x^{2} - y^{2} = (x + y) (x - y)$ $x^2 - y^2 = (x + y)(x - y)$

The perfect square of $16 x^{2}$ $16x^2$ is $4 x$ $4x$
The perfect square of 36 is 6

$16 x^{2} - 36$ $16x^2 - 36$ = (4x + 6)(4x - 6)

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How do you factor $16 x^{2} - 36$ $16x^2-36$ using the difference of squares?

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How do you factor $16 x^{2} - 36$ $16x^2-36$ using the difference of squares?