How do you factor $x^{3} + 64$ $x^3+64$ ?

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Answer 1 · 2015-02-02T17:35:44

The answer is: $x^{3} + 64 = (x + 4) (x^{2} - 4 x + 16)$ $x^3+64=(x+4)(x^2-4x+16)$ .

It's easy if we remember the formula of sum of cubes, that says:

$x^{3} + y^{3} = (x + y) (x^{2} - x y + y^{2})$ $x^3+y^3=(x+y)(x^2-xy+y^2)$ .

In this case $64 = 4^{3}$ $64=4^3$ .

It's also to remember the formula of difference of cubes, that says:

$x^{3} - y^{3} = (x - y) (x^{2} + x y + y^{2})$ $x^3-y^3=(x-y)(x^2+xy+y^2)$ .

How do you factor x^3+64x3+64x^3+64?