How do you factor $x^{3} + 343$ $x^3+343$ ?

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How do you factor $x^{3} + 343$ $x^3+343$ ?

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Answer 1 · 2018-04-15T10:40:30

$(x + 7) (x^{2} - 7 x + 49)$ $(x+7)(x^2-7x+49)$

Explanation:

$this is a sum of cubes$ $"this is a "color(blue)"sum of cubes"$

$∙ x a^{3} + b^{3} = (a + b) (a^{2} - a b + b^{2})$ $•color(white)(x)a^3+b^3=(a+b)(a^2-ab+b^2)$

$here a = x and 343 = 7^{3} \Rightarrow b = 7$ $"here "a=x" and "343=7^3rArrb=7$

$\Rightarrow x^{3} + 343 = (x + 7) (x^{2} - 7 x + 49)$ $rArrx^3+343=(x+7)(x^2-7x+49)$

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How do you factor $x^{3} + 343$ $x^3+343$ ?

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