How do you factor $49t^2 - 81s^2$ ?

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Answer 1 · 2015-07-10T13:59:09

Can be: $(7t+9s)(7t-9s)$

Both the terms you have are squares so that you can use:
$a^2-b^2=(a+b)(a-b)$
in your case:
$49t^2-81s^2=(7t+9s)(7t-9s)$

How do you factor 49t^2 - 81s^249t^2 - 81s^2?