How do you factor $6 k^{2} h^{4} - 54 k^{4}$ $6k^2h^4-54k^4$ ?

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Answer 1 · 2017-06-30T18:52:46

$6 k^{2} (h^{2} - 3 k) (h^{2} + 3 k)$ $6k^2(h^2-3k) (h^2+3k)$

Factor the $6 k^{2}$ $6k^2$ out first:

$6 k^{2} (h^{4} - 9 k^{2})$ $6k^2(h^4 -9k^2)$

You're left with the difference of two squares.

How do you factor 6k^2h^4-54k^46k2h4−54k46k^2h^4-54k^4?