How do you factor 9-(k+3)^2?
1 Answer
May 2, 2017
Explanation:
This expression is a
color(blue)"difference of squares" which factorises in general as.
color(red)(bar(ul(|color(white)(2/2)color(black)(a^2-b^2=(a-b)(a+b))color(white)(2/2)|)))
"for " 9-(k+3)^2
a=3" and " b=k+3
rArr9-(k+3)^2=(3-(k+3))(3+(k+3))
color(white)(rArr9-(k+3)^2)=(3-k-3)(6+k)
color(white)(rArr9-(k+3)^2)=-k(6+k)