How do you factor $y^3+27$ ?

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Answer 1 · 2016-07-23T22:04:30

$(y+3)(y^2 -3y + 9)$

This is the sum of two cubes. $(y^3 +27)$

Once recognised it is easily factored because the factors follow the same pattern

$y^3 + 27$
= $(y+3)(y^2 -3y + 9)$

How do you factor y^3+27y^3+27?