How do you factor $5 x^{3} - 40$ $5x^3 - 40$ ?

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Answer 1 · 2017-07-18T15:57:28

$a^{3} - b^{3} = (a - b) (a^{2} + a b + b^{2})$ $a^3-b^3=(a-b)(a^2+ab+b^2)$

$5 x^{3} - 40 = 5 (x^{3} - 8) = 5 (x^{3} - 2^{3}) = 5 (x - 2) (x^{2} + 2 x + 4)$ $5x^3-40=5(x^3-8)=5(x^3-2^3)=5(x-2)(x^2+2x+4)$

How do you factor 5x^3 - 405x3−405x^3 - 40?