How do you factor a^4-18a^2+81? Algebra Polynomials and Factoring Factor Polynomials Using Special Products 1 Answer Alan N. Aug 14, 2016 (a-3)^2(a+3)^2 Explanation: a^4-18a^2+81 Factorise: (a^2-9)(a^2-9) =(a^2-3^2)(a^2-3^2) =(a+3)(a-3)(a+3)(a-3) =(a-3)^2(a+3)^2 Answer link Related questions How do you factor special products of polynomials? How do you identify special products when factoring? How do you factor x^3 -8? What are the factors of x^3y^6 – 64? How do you know if x^2 + 10x + 25 is a perfect square? How do you write 16x^2 – 48x + 36 as a perfect square trinomial? What is the difference of two squares method of factoring? How do you factor 16x^2-36 using the difference of squares? How do you factor 2x^4y^2-32? How do you factor x^2 - 27? See all questions in Factor Polynomials Using Special Products Impact of this question 3277 views around the world You can reuse this answer Creative Commons License