How do you factor $81 x^{4} - 256$ $81x^4 -256$ ?

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How do you factor $81 x^{4} - 256$ $81x^4 -256$ ?

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Answer 1 · 2018-04-18T11:45:10

$(9 x^{2} + 16) (3 x + 4) (3 x - 4)$ $(9x^2+16)(3x+4)(3x-4)$

Explanation:

Using the difference of two squares ( $a^{2} - b^{2} = (a + b) (a - b)$ $a^2-b^2=(a+b)(a-b)$ ) we can get:
$(9 x^{2} + 16) (9 x^{2} - 16)$ $(9x^2+16)(9x^2-16)$

$9 x^{2} - 16 = (3 x + 4) (3 x - 4)$ $9x^2-16=(3x+4)(3x-4)$

$(9 x^{2} + 16) (3 x + 4) (3 x - 4)$ $(9x^2+16)(3x+4)(3x-4)$

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How do you factor $81 x^{4} - 256$ $81x^4 -256$ ?

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