How do you factor $10 x^{3} - 270$ $10x^3-270$ ?

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Answer 1 · 2016-06-25T08:39:23

$= 10 (x - 3) (x^{2} + 3 x + 9)$ $=10(x-3)(x^2+3x+9)$

Always look for a common factor first. IN this case it is 10.

$10 (x^{3} - 27) difference of cubes$ $10(x^3 -27) " difference of cubes"$

$= 10 (x - 3) (x^{2} + 3 x + 9)$ $=10(x-3)(x^2+3x+9)$

How do you factor 10x^3-27010x3−27010x^3-270?