How do you factor gx^2 - 3hx^2 - 6fy^2 - gy^2 + 6fx^2 + 3hy^2? Algebra Polynomials and Factoring Factor Polynomials Using Special Products 1 Answer Ratnaker Mehta Aug 4, 2016 (x+y)(x-y)(g-3h+6f). Explanation: Rearranging the terms, the Expression =gx^2-gy^2-3hx^2+3hy^2+6fx^2-6fy^2 =g(x^2-y^2)-3h(x^2-y^2)+6f(x^2-y^2) =(x^2-y^2)(g-3h+6f) =(x+y)(x-y)(g-3h+6f). Answer link Related questions How do you factor special products of polynomials? How do you identify special products when factoring? How do you factor x^3 -8? What are the factors of x^3y^6 – 64? How do you know if x^2 + 10x + 25 is a perfect square? How do you write 16x^2 – 48x + 36 as a perfect square trinomial? What is the difference of two squares method of factoring? How do you factor 16x^2-36 using the difference of squares? How do you factor 2x^4y^2-32? How do you factor x^2 - 27? See all questions in Factor Polynomials Using Special Products Impact of this question 4557 views around the world You can reuse this answer Creative Commons License