How do you factor ${(4 x - 3)}^{2} - {(x + 1)}^{2}$ $(4x-3)^2 - (x+1)^2$ ?

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Answer 1 · 2015-05-08T17:43:32

(3x-4)(5x-2)

Use the identity $a^{2} - b^{2}$ $a^2-b^2$ = (a-b)(a+b). Factors would be (4x-3-x-1)(4x-3+x+1)

(3x-4)(5x-2)

How do you factor (4x-3)^2 - (x+1)^2(4x−3)2−(x+1)2(4x-3)^2 - (x+1)^2?