How do you factor $4x^2 - 16$ ?

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Answer 1 · 2015-07-03T16:39:40

So, $4x^2 -16 =color(blue)((2x+4)(2x-4)$ .

$4x^2 - 16$ is of the form $color(blue)(a^2 - b^2$ (where $a=2x , b=4)$ , and as per the identity:
$color(blue)(a^2 - b^2= (a+b)(a-b)$

So, $4x^2 -16 =color(blue)((2x+4)(2x-4)$ .

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