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How do you factor $64 - 4 x^{2}$ $64 - 4x^2$ ?

1 Answer

Konstantinos Michailidis

Apr 22, 2016

We have that

$64 - 4 x^{2} = {(8)}^{2} - {(2 x)}^{2} = (8 - 2 x) \cdot (8 + 2 x)$ $64-4x^2=(8)^2-(2x)^2=(8-2x)*(8+2x)$

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