How do you factor 316 - 343t^3? Algebra Polynomials and Factoring Factor Polynomials Using Special Products 1 Answer sankarankalyanam Oct 5, 2017 (6-7t)(36+42t+t^2) Explanation: Assuming the question as 216-343t^3 as suggested by Mr George, a^3-b^3=(a-b)(a^2+ab+b^2 6^3=216 Hence a=6 & 7^3=343 and hence b=7. The factors are (6-7t)(6^2+(6*7t)+(7t)^2) (6-7t)(36+42t+t^2) Answer link Related questions How do you factor special products of polynomials? How do you identify special products when factoring? How do you factor x^3 -8? What are the factors of x^3y^6 – 64? How do you know if x^2 + 10x + 25 is a perfect square? How do you write 16x^2 – 48x + 36 as a perfect square trinomial? What is the difference of two squares method of factoring? How do you factor 16x^2-36 using the difference of squares? How do you factor 2x^4y^2-32? How do you factor x^2 - 27? See all questions in Factor Polynomials Using Special Products Impact of this question 1378 views around the world You can reuse this answer Creative Commons License