How do you factor $a^2+16a+64$ using the perfect squares formula?

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Answer 1 · 2016-07-25T16:54:38

$a=-8$

$a^2+16a+64=0$
or
$a^2+16a+8^2=0$
or
$a^2+2(a)(8)+8^2=0$
or
$(a+8)^2=0$
or
$a+8=0$
or
$a=-8$

How do you factor a^2+16a+64a^2+16a+64 using the perfect squares formula?