How do you factor a perfect square trinomial #36b^2 − 24b + 16#? Algebra Polynomials and Factoring Factor Polynomials Using Special Products 1 Answer Tessalsifi · Olivier B. Jun 12, 2015 We know that #(color(blue)a-color(red)b)²=color(blue)(a^2)-2color(blue)acolor(red)b+color(red)(b²)# #36b^2=color(blue)((6b)²)=color(blue)(a^2)# ( #color(blue)(a=6b# ) #16=color(red)(4^2)=color(red)(b^2)# ( #color(red)(b=4# ) We are going to check if #-2ab=-24b# : #-2ab=-2*6b*4=-48b# : incorrect Thus #36b^2-24b+16# is not a perfect square. Answer link Related questions How do you factor special products of polynomials? How do you identify special products when factoring? How do you factor #x^3 -8#? What are the factors of #x^3y^6 – 64#? How do you know if #x^2 + 10x + 25# is a perfect square? How do you write #16x^2 – 48x + 36# as a perfect square trinomial? What is the difference of two squares method of factoring? How do you factor #16x^2-36# using the difference of squares? How do you factor #2x^4y^2-32#? How do you factor #x^2 - 27#? See all questions in Factor Polynomials Using Special Products Impact of this question 2538 views around the world You can reuse this answer Creative Commons License