How do you factor $24c^3t^2+26c^2t^3+6ct^4$ ?

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Answer 1 · 2016-07-16T11:23:28

$2ct^2(3c+t)(4c+3t)$

$24c^3t^2+26c^2t^3+6ct^4 = 2ct^2(12c^2+13ct+3t^2)=2ct^2(12c^2+9ct+4ct+3t^2)=2ct^2(3c(4c+3t)+t(4c+3t))=2ct^2(3c+t)(4c+3t)$ [Ans]

How do you factor 24c^3t^2+26c^2t^3+6ct^424c^3t^2+26c^2t^3+6ct^4?