How do you factor $y= x^2 + 3x - 10$ ?

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Answer 1 · 2016-05-13T18:20:16

$y = x^2+3x-10 = (x+5)(x-2)$

Find a pair of factors of $10$ which differ by $3$ .

The pair $5, 2$ works, hence:

$x^2+3x-10 = (x+5)(x-2)$

How do you factor y= x^2 + 3x - 10 y= x^2 + 3x - 10 ?