How do you factor $y=4x^2+12x+9$ ?

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Answer 1 · 2016-02-06T00:16:05

$(2x+3)^2$

A special case of the quadratic polynoms is

$(a+b)^2= a^2+2ab+b^2$

We can see that a=2x and b=3

Therefore the factorization is:

$(2x+3)^2$

How do you factor y=4x^2+12x+9 y=4x^2+12x+9 ?