How do you factor $a^{3} + b^{3} + a + b$ $a^3 + b^3 + a + b$ ?

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Answer 1 · 2015-07-09T20:34:49

$a^{3} + b^{3} + a + b = (a + b) (a^{2} - a b + b^{2}) + (a + b)$ $a^3+b^3+a+b = (a+b)(a^2-ab+b^2)+(a+b)$

$= (a + b) (a^{2} - a b + b^{2} + 1)$ $=(a+b)(a^2-ab+b^2+1)$

Use the sum of cubes identity:

$a^{3} + b^{3} = (a + b) (a^{2} - a b + b^{2})$ $a^3+b^3 = (a+b)(a^2-ab+b^2)$

How do you factor a^3 + b^3 + a + ba3+b3+a+ba^3 + b^3 + a + b?