How do you factor $8c^3-8c$ ?

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Answer 1 · 2018-05-21T20:12:09

See a solution process below:

There common factor for each term is: $color(red)(8c)$ :

$8c^3 = color(red)(8c) * c^2$

$8c = color(red)(8c) * 1$

We can then factor as:

$8c^3 - 8c => (color(red)(8c) * c^2) - (color(red)(8c) * 1) => color(red)(8c)(c^2 - 1)$

$c^2 - 1$ is a special form of the quadratic where:

$c^2 - 1 = (c + 1)(c - 1)$

$color(red)(8c)(c^2 - 1) => color(red)(8c)(c + 1)(c - 1)$

How do you factor 8c^3-8c8c^3-8c?