How do you factor $p^{2} - 100$ $p^2-100$ ?

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Answer 1 · 2018-03-13T22:32:12

$(p - 10) (p + 10)$ $(p-10)(p+10)$

$p^{2} - 100$ $p^2-100$

Here you can simplify this by using the difference of two squares

$a^{2} - b^{2} = (a - b) (a + b)$ $a^2 - b^2 = (a-b)(a+b)$

and you will have

$p^{2} - 10^{2}$ $p^2-10^2$

Then you can simplify this furthermore

$(p - 10) (p + 10)$ $(p-10)(p+10)$

as the final answer.

How do you factor p^2-100p2−100p^2-100?