How do you factor #64y^3 - 125#?
1 Answer
May 24, 2015
Use identity: a^3 - b^3 = (a - b)(a^2 + ab + b^2)
64y^3 - 125 = (4y - 5)(16y^2 + 20y + 25)
Use identity: a^3 - b^3 = (a - b)(a^2 + ab + b^2)
64y^3 - 125 = (4y - 5)(16y^2 + 20y + 25)