Question #0f218

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Question #0f218

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Answer 1 · 2016-11-08T21:48:32

$10 z^{2} (z - 16) (4 z^{2} - z + 8)$ $10z^2(z-16)(4z^2-z+8)$

Explanation:

$40 z^{4} (z - 16) - 10 z^{3} (z - 16) + 80 z^{2} (z - 16) = (z - 16) (40 z^{4} - 10 z^{3} + 80 z^{2}) = 10 z^{2} (z - 16) (4 z^{2} - z + 8)$ $40z^4(z−16)−10z^3(z−16)+80z^2(z−16)=(z-16)(40 z^4 - 10 z^3 + 80 z^2)=10z^2(z-16)(4z^2-z+8)$

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Question #0f218

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