What is the special product form of the expression $9x^8-4$ ?

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Answer 1 · 2017-10-17T23:32:10

This expression is known as the difference of two squares.

We have $a^2-b^2=(a+b)(a-b)$ for any $a,b in RR$ .

Thus $9x^8-4=(3x^4+2)(3x^4-2)$

What is the special product form of the expression 9x^8-49x^8-4?