How do you factor ${(b + 2)}^{2} - {(b - 2)}^{2}$ $(b+2)^2 - (b-2)^2$ ?

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How do you factor ${(b + 2)}^{2} - {(b - 2)}^{2}$ $(b+2)^2 - (b-2)^2$ ?

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Answer 1 · 2015-12-06T01:45:28

$8 b$ $8b$

Explanation:

$p^{2} - q^{2} = (p + q) (p - q)$ $p^2 - q^2 = (p+q)(p-q)$

If $p = (b + 2)$ $p = (b+2)$ and $q = (b - 2)$ $q = (b-2)$
Then the expression to be factored = $((b + 2) + (b - 2)) ((b + 2) - (b - 2))$ $((b+2) + (b-2))((b+2) - (b-2))$
$= (2 b) (4)$ $= (2b)(4)$
= $8 b$ $8b$

This result can also be shown by simply expanding both square terms of the expression:

$(b^{2} + 4 b + 4) - (b^{2} - 4 b + 4) = 8 b$ $(b^2 + 4b + 4) - (b^2 -4b + 4) = 8b$

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How do you factor ${(b + 2)}^{2} - {(b - 2)}^{2}$ $(b+2)^2 - (b-2)^2$ ?

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Explanation:

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How do you factor (b+2)^2 - (b-2)^2(b+2)2−(b−2)2(b+2)^2 - (b-2)^2?

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How do you factor ${(b + 2)}^{2} - {(b - 2)}^{2}$ $(b+2)^2 - (b-2)^2$ ?