How do you factor the difference of two cubes $x^{3} - 64$ $x^3-64$ ?

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Answer 1 · 2015-02-04T01:26:07

Excuse me if I'll be short, but there's not much to explain. The general formula states that

$a^{3} - b^{3} = (a - b) (a^{2} + a b + b^{2})$ $a^3 - b^3 = (a- b)(a^2+ab+b^2)$

So, in your case, since $a = x$ $a=x$ and $b = 4$ $b=4$ ,

$x^{3} - 64 = (x - 4) (x^{2} + 4 x + 16)$ $x^3-64 = (x-4)(x^2+4x+16)$

How do you factor the difference of two cubes x^3-64x3−64x^3-64?