Question #23690

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Answer 1 · 2016-06-09T02:58:28

Logarithmic equation ${log}_{\frac{1}{4}} 256 = - 4$ $log_(1/4) 256=-4$

Exponential equation ${(\frac{1}{4})}^{- 4} = 256$ $(1/4)^(-4)=256$

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Logarithmic Equation takes the form

${log}_{b} M = x$ $log_b M=x$

Exponential Equation takes the form

$b^{x} = M$ $b^x=M$

The given logarithmic equation is ${log}_{\frac{1}{4}} 256 = - 4$ $log_(1/4) 256=-4$

and $b = \frac{1}{4}$ $b=1/4$ and $M = 256$ $M=256$ and $x = - 4$ $x=-4$

Therefore, its exponential form is

$b^{x} = m = M$ $b^x=m=M$

${(\frac{1}{4})}^{- 4} = 256$ $(1/4)^(-4)=256$

God bless....I hope the explanation is useful.