How do you factor $16x^2-9=0$ ?

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Answer 1 · 2015-05-17T08:23:36

property : $color(blue)(a^2 - b^2 = (a+b)(a-b)$

the expression given is:
$16 x^2 - 9 = 0$
$(4x)^2 - 3^2 = 0$

note : $a = 4x and b =3$

the expression now becomes:
$(4x)^2 - 3^2 = (4x +3) (4x-3)$ , this is the factorised form.

How do you factor 16x^2-9=0 16x^2-9=0?