How do you factor $2x^2 − 6x − 36$ ?

Question

3728 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-05-12T00:29:20

$f(x) = 2(x^2 - 3x - 18)$ = 2(x - p)(x - q)

Use the new AC Method to factor the trinomial.

Compose factor pairs of c = -18. Proceed: (-1, 18)(-2, 9)(-3, 6). This last sum is (6 - 3 = 3 = -b). Then p = 3 and q = -6.

Answer: f(x) = 2(x + 3)(x - 6)

How do you factor 2x^2 − 6x − 362x^2 − 6x − 36?