How do you factor $x^3y^2-xy^4$ ?

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Answer 1 · 2015-07-12T21:00:03

I found: $xy^2(x-y)(x+y)$

you can collect $xy^2$ and remember that $a^2-b^2=(a+b)(a-b)$ to get:
$xy^2(x^2-y^2)=xy^2(x-y)(x+y)$

How do you factor x^3y^2-xy^4x^3y^2-xy^4?