How do you factor $2y^3 - 54z^3$ ?

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Answer 1 · 2015-12-16T17:39:31

$2y^{3}-54z^{3}=2(y^{3}-27z^{3})=2(y-3z)(y^{2}+3yz+9z^{2})$

Use the formula for factoring the difference of two cubes:

$a^{3}-b^{3}=(a-b)(a^{2}+ab+b^{2})$ (check this by expanding the right hand side).

For the expression $y^{3}-27z^{3}$ , use $a=y$ and $b=3z$ .

How do you factor 2y^3 - 54z^32y^3 - 54z^3?